10x^2/3=448

Solution for 10x^2/3=448 equation:

10x^2/3=448

We move all terms to the left:

10x^2/3-(448)=0

We multiply all the terms by the denominator


10x^2-448*3=0

We add all the numbers together, and all the variables

10x^2-1344=0

a = 10; b = 0; c = -1344;
Δ = b2-4ac
Δ = 02-4·10·(-1344)
Δ = 53760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{53760}=\sqrt{256*210}=\sqrt{256}*\sqrt{210}=16\sqrt{210}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{210}}{2*10}=\frac{0-16\sqrt{210}}{20}
=-\frac{16\sqrt{210}}{20}
=-\frac{4\sqrt{210}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{210}}{2*10}=\frac{0+16\sqrt{210}}{20}
=\frac{16\sqrt{210}}{20}
=\frac{4\sqrt{210}}{5}
$